The annual MVP question. It comes down to so many objective views...
Do you choose the best player on the best team? The player who's team is most dependent upon him? The highest scorer? The most exciting player? How about the winner of a league-wide 1-on-1 tourney? Or should the award go to the league's most valuable asset?
Of course, this season, the question is much simpler: are you for Kobe, or are you for LeBron?
In this post-MJ NBA, we are endlessly searching for a player cast in His Airness' image. Someone who fills the role of both athletic dominance and ad time. Skill with a smile. That’s our MVP.
Well guess what, America? You got two of them. You lucky bastards.
LeBron and Kobe are two of HIS mold. They both have the ability to take basketball beyond the game, where third-world children miles from a working television know their name. They have the raw dominance to win games by sheer will alone. They are both among the best spot-shooters in the league, while also being the two best finishers in the league (just unfair). And neither are slouches at passing either.
Oh, and as luck would have it, they are both in their primes.
Watch either of them for any extended period, and you become absolutely convinced of their MVP likelihood. How could it get any better than this? Who could possibly be more deserving? Think what's gone down in even the last two weeks:
52 points. (Kobe)
Then, two nights later, 50-10 and 8 rebounds. (LeBron)
A thunderous throwdown right in the grill of the Phoenix Suns:
Oh, but here's a hang-time poster dunk on the Bulls:(:52 mark…unreal.)
When handed a pair of Jordans, which do you choose?
Both. You wear them both.
That is why, this year, LeBron James and Kobe Bryant should be co-MVPs. They both possess the talents, and they are both obviously worthy. And again, leaving either out would be a disservice to them, the MVP, and basketball in general.
We are all witnesses, LeBron says. Yes, we are. It is indeed The Second Coming, and we have been blessed...with two.
Let me hear your thoughts.